Question

check whether the equation 1/2mv^2=mgh is dimensionally correct, where m is the mass of the body,v, its velocity,g is the acceleration due to gravity.​

Answer 1

Explanation:

1/2mv^2=mgh

m=M, v=LT^-1

g=LT^-2,h=L

Then....

ML^2T^-2=ML^2T^-2

Hence proved