Check whether the equation 6x square-7x+2=0 has real roots,if it has find them by completing square method
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D=b^2 -4ac = (-7)^2 - 4(6)(2) = 1D > 0 hence, this equation has real roots.
6x^2 -7x = -2x^2 - 7/6 x = -1/3x^2 - 7/6 x + 49/36 = 49/36 - 1/3(x - 7/6)^2 = 37/36x = √37+7÷6 and -√37+7÷6
6x^2 -7x = -2x^2 - 7/6 x = -1/3x^2 - 7/6 x + 49/36 = 49/36 - 1/3(x - 7/6)^2 = 37/36x = √37+7÷6 and -√37+7÷6
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