Question

check whether the equation is dimensionally correct.T=2π√m/g​

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

Given expression :-

$t = 2\pi \sqrt{ \frac{m}{g} }$

Left hand side it has : T

Right hand side : 2π is constant and M = M and G = LT^-2

$t = \sqrt \frac{m}{m {t}^{ - 2} }$

After cancelling m by m we get 1/ T^-2, and by reversing it will become T^2

$t = \sqrt{ {t}^{2} }$

Under root will get cancelled by Square and we will left by only t on right hand side also.

$t \: = \: t$

Thus, DIMENSIONALLY CORRECT!