Physics, asked by questioner68, 1 month ago

check whether the equation is
dimensionally correct
v² = u² + 2as²​

Answers

Answered by jasimmuhammed932
3

Answer:

it is dimensionally correct

[V²]=(LT–1)²

=L²T^-2

[U²]=(LT–1)²

= L² T^-2

[2as]=LT^-2× L

=L² T^–2

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