Question

Check whether the equation is dimensionally correct x = x0 + v0t + ½ at2

Answer 1

Explanation:

x= x0+v0t+1/2at²

if this eqn is correct then

dimension of lLHS = dimension of RHS

Dimension of LHS

= [M°L1T°]

Dimension of RHS

= [M°L1T°]+ [ M°L1T-1 ] [ M°L°T1]+[M°L1T-2] [M°L°T2]

= [M°L1T°]+[M°L1T°] + [ M°L1T°]

= [ M°L1T°]

= dimension ofLHS

thus this eqn is true.

Answer 2

Answer:

Explanation:

x= x0+v0t+1/2at²

if this eqn is correct then

dimension of lLHS = dimension of RHS

Dimension of LHS

= [M°L1T°]

Dimension of RHS

= [M°L1T°]+ [ M°L1T-1 ] [ M°L°T1]+[M°L1T-2] [M°L°T2]

= [M°L1T°]+[M°L1T°] + [ M°L1T°]

= [ M°L1T°]

= dimension ofLHS

Hence the  equation is correct