Check whether the equation mv2=mgh dimensionally correct ?
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Explanation:
dimension of mv2 = [ M] [LT^-1]^2
=[ML^2T^-2]...............(1)
dimension of mgh =[ MLT^-2L]
=[ ML^2T^-2]..............(2)
as eq 1 and eq 2 are same so the equation is dimensionally correct
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