Check whether the following are quadratic eqn:-
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If they are quadratic equation, so it should be expressed in the form of (ax² + bx + c = 0), a ≠ 0,but b can be equal to 0
Note : above process is also known as factorisation but in quadratic equation we will get 2 values of x,
Checking :-
(x + 1)² = 2(x - 3)
x² + 1² + 2(1)(x) = 2x - 6
x² + 1 + 2x =2x - 6
x² + 1 + 2x - 2x + 6 = 0
x² + 7 =0
x² = -7
x = ±√(-7)
We got 2 values of x,
In this, x² + 7 = 0
[ax² + bx + c = 0]
a = 1
b = 0
c = 7
Hence, they are in quadratic equation.
I hope this will help you
(-:
Note : above process is also known as factorisation but in quadratic equation we will get 2 values of x,
Checking :-
(x + 1)² = 2(x - 3)
x² + 1² + 2(1)(x) = 2x - 6
x² + 1 + 2x =2x - 6
x² + 1 + 2x - 2x + 6 = 0
x² + 7 =0
x² = -7
x = ±√(-7)
We got 2 values of x,
In this, x² + 7 = 0
[ax² + bx + c = 0]
a = 1
b = 0
c = 7
Hence, they are in quadratic equation.
I hope this will help you
(-:
mysticd:
x² + 7 = 0 is a quadratic equation
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