Question

check whether the following are quadratic equation
(x-2)(x+1) = (x-1)(x+3)

Answer 1

$\huge\red{\boxed{\underline{ANSWER}}}$

$(x - 2)(x + 1) = (x - 1)(x + 3) \\ \implies \: \cancel{x}^{2} - x - 2 = \cancel{x}^{2} + 2x - 3 \\ \implies \: 3x - 1 = 0$

There is no term in is the power of 2 of x .So this expansion is not a quadratic equation.

Answer 2

Solution ⤵

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$\bf{{=> (x-2) (x+1) = (x-1) (x+3)}}$

$\bf{{=> {x}^{2} + x - 2x - 2 = {x }^{2} + 3x - x - 3 = 0 }}$

$\bf{{=> {x}^{2} + x - 2x - 2 - {x}^{2} - 3x + x + 3 = 0 }}$

$\bf{{=>x - 2x - 2 - 3x + x + 3 = 0 }}$

$\bf{{=> - 3x + 1 = 0}}$

Here, degree of equation is 1.

Therefore, it is not a Quadratic Equation

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