Check whether the following are quadratic equations.
1) (x - 2) (x + 1) = (x - 1) (x - 3)
2) (x - 3) (2x - 1) = x ( x + 5)
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Answer is in the above attachment
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Step-by-step explanation:
1) (x - 2) (x + 1) = (x - 1) (x - 3)
→ x² + x - 2x - 2 = x² + 3x - x - 3 .
→ x² + x - 2x + 2 - x² - 3x + x + 3 = 0 .
→ - 3x + 5 = 0 ≠ ax² + bx + c = 0 .[ where a ≠ 0 ] .
So, it is not in the form of quadratic equation.
2) (x - 3) (2x - 1) = x ( x + 5).
→ 2x² + x - 6x - 3 = x² + 5x .
→ 2x² + x - 6x - 3 - x² - 5x = 0 .
→ 2x² - 10x - 3 = 0 = ax² + bx + c = 0 [ where a≠ 0 ] .
Yes, it is in the form of quadratic equation.
Hence, it is solved.
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