Question

Check whether the following are quadratic equations and express in standard form : i) ( x-2 ) ( x + 1) = (x-1) ( x+3) ii) x2 + 3x + 2 = (x-2)2 iii) +1 = −2 iv) (+2)2 = +1 + 1 v) x3 -4x2 –x + 1 = ( x-2)2

Answer 1

Answer:

If you have an equation of the form "ax2 + bx + c = 0", we can solve it for you. ... In disguise, In standard form, a, b and c. x2 = 3x -1, x2 - 3x + 1 = 0, a=1, b=-3, c=1. 2(x2 - 2x) = 5, 2x2 - 4x - 5 = 0, a=2, b=-4, c=-5 ... If it is positive, you will get two normal solutions, if it is zero you get just ONE solution