Question

check whether the following are quadratic equations or not (x+2)cube=3x(xsquare+4)​

Answer 1

Answer:

Step-by-step explanation:

The answer is, it is not a quadratic equation.

Because, the degree of x is not x square, that is the highest degree of x is not square.

Answer 2

Answer:

it is very simple

Step-by-step explanation:

(x+2)^3=3(x^2+4)

first LHS

now, by using property

(x+y)^3=x^3 + 3x^2y + 3xy^2 + y^3

by putting values

(x+2)^3= x^3 + 3x^2*2 + 3x*2^2 + 2^3

=x^3 + 6x^2 + 3x*4 + 8

=x^3 + 6x^2 + 12x + 8 -----------1

now, by solving RHS

3(x^2+4)

=3x^2 + 12 ------------2

as,we know LHS=RHS

x^3 + 6x^2 + 12x + 8 = 3x^2 + 12

by sending 3x^2 + 12 on the other side

x^3 + 6x^2 - 3x^2 + 12x + 8 - 12 = 0

x^3 + 3x^2 + 12x - 4 = 0

so, as it ' s highest power is cube (x^3)

it is not a quadratic equation