Question

check whether the following equation is quadratic equation:-
x²-4x-x+1=(x-2)³​​

Answer 1

Answer:

x²-4x-x+1=(x-2)³

x² -5x +1 = (x³ -y³ -3x²y +3xy²)

x² -5x +1 = ( x³ -8 - 6x²+ 12x)

x² - 5x + 1 - x³ + 8 + 6x² - 12x = 0

- x³ + 7x² - 17x +9 =

So it's not a quadratic equation it's cubic

Step-by-step explanation:

Answer 2

Answer:

$\Large \underline{\tt Solution} :-$

$\tt \dashrightarrow x^2 - 4x - x + 1 = (x-2)^3$

By using identity :

• $\large \underline{\boxed{\bf{(a-b)^3 = a^3 - b^3 -3a^2b + 3ab^2}}}$

$\tt \dashrightarrow x^2 - 5x + 1 = (x)^3 - (2)^3 - 3(x)^2 (2) + 3(x)(2)^2$

$\tt \dashrightarrow x^2 - 5x + 1 = x^3 - 8 - 6x^2 + 3x \times 4$

$\tt \dashrightarrow x^2 - 5x + 1 = x^3 - 8 - 6x^2 + 12x$

$\tt \dashrightarrow x^2 - 5x + 1 - x^3 + 8 + 6x^2 - 12x = 0$

$\tt \dashrightarrow - x^3 + 7x^2 - 17x + 9 = 0$

As, it isn't in form of ax² + bx + c = 0,

Therefore it isn't quadratic equation.