check whether the following functions are 1-1 or onto function.Solve with proper steps
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for the function to be one one..
f(x1)=f(x2)
x1+3/x1-1 = x2+3/ x2-1
since x1= x2
it is one one
For the function to be onto the range of the function must be in the given range of R ...which is {R} - 1 ..so it is onto
f(x1)=f(x2)
x1+3/x1-1 = x2+3/ x2-1
since x1= x2
it is one one
For the function to be onto the range of the function must be in the given range of R ...which is {R} - 1 ..so it is onto
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