Question

check whether the following is a quadratic equation
∆ (4x-2)² - (6+x) = (2x-1)²-(4x+9)
∆ (x-3)³ = 9x(5x² - 9)
∆ (5x-4x)-(9-6x)=(7x²-9)(x-3)
∆(x-2)²+9=2x-7
∆x(2x+5)=(X2+1)(x²-9x) ​

Answer 1

___✅ᴀɴsᴡᴇʀ ✅___

1) x2 + 5x – 2 = 0

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(2) y2 = 5y – 10

Only one variable y.

Maximum index = 2

So, it is a quadratic equation.

(3) y2+

1

y

=2

⇒y3+1=2y

Only one variable y.

Maximum index = 3

So, it is not a quadratic equation.

(4) x+

1

x

=-2

⇒x2+1=-2x

Only one variable x.

Maximum index = 2

So, it is a quadratic equation.

(5) (m + 2) (m – 5) = 0

⇒m2-3m-10=0

Only one variable m.

Maximum index = 2

So, it is a quadratic equation.

(6) m3 + 3m2 – 2 = 3m3

Only one variable m.

Maximum index = 3

So, it is not a quadratic equation.

__ʜᴏᴘᴇ ɪᴛ's ʜᴇʟᴘғᴜʟ ᴛᴏ ʏᴏᴜ __

Answer 2

Answer:

HEYA MATE !!

HERE IS UR ANS ⤵️⤵️

(4x-2)² - (6+x) = (2x-1)² - (4x+9)

• (16x-4) - (6+x) = (4x-1) - (4x+9)
• (16x+x) - (-4+6) = (4x+4x) - (-1+9)
• 17x - 2 = 8x - 8
• 17x - 8x = 2 - 8
• 9x = -2
• x = -2/9

... HOPE THIS HELPS U ALMOST ...

... THANK Q ...