Math, asked by shanon2005, 5 months ago

Check whether the following is a quadratic equation
(x-2)3=x3-4x2+x+1​

Answers

Answered by Anonymous
3

Solution :-

Simply the given equation:

 \sf \to \: (x - 2) {}^{3} = x {}^{3}  - 4x {}^{2}  + x + 1 \\   \sf\to \: x {}^{3}  - 6x {}^{2}  + 12x - 8 = x {}^{3} - 4x {}^{2}   + x + 1 \\  \sf \to \:  - 6x {}^{2}  + 4x {}^{2}  + 12x - x - 8 -1 =  0 \\  \sf \to \:  \green{\bf{- 2x {}^{2}  + 11x - 9 = 0}}

∴ The following equation is in the form of ax²+bx-c =0, so it's a quadratic equation.

Used identity:

(a-b)³ = (a-b)³=a³-3a²b+3ab²-b³

Answered by Anonymous
1

Step-by-step explanation:

here's your answer.............

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