Question

check whether the following is quadratic equation?
$1) {(x + 1)}^{2} = 2(x - 3)$
$2) {x}^{2} - 2x = ( - 2)(3 - x)$
​

Answer 1

Step-by-step explanation:

1)(x+1)^2=2(x-3)

x^2+2x+1-2x+6=0

x^2+7=0

since, x^2+7 is a quadric equation

therefore (x+1)^2=2(x-3) is a quadratic equation....

2)x^2-2x=-6+2x

x^2-2x-2x+6=0

x^2-4x+6=0

since, x^2-4x+6 is quadratic equation.

therefore x^2-2x=(-2)(3-x) is a quadratic equation

Answer 2

Answer:

$\huge\boxed{\fcolorbox{Blue}{Pink}{Answer}}$

$1) {(x + 1)}^{2} = 2(x - 3)$

${x}^{2} + 2x + 1 = 2x - 6$

${x}^{2} + 2x - 2x + 1 + 6 = 0$

${x}^{2} + 7 = 0$

$hence \: this \: is \: a \: quadrtic\: equation$

$2) {x}^{2} - 2x = ( - 2)(3 - x)$

${x}^{2} + 2x = ( -6) + 2x$

${x}^{2} + 6 = 0$

$hence \: this \: is \: a \: quadratic \: equation$

Hope this help u ❤️❤️