Question

Check whether the formula is dimensionally correct:
h = (2S cos(theta))/rdg
h is height of liqud,
S is surface tension, r is the radius, d is density of liquid and g is acceleration due to gravity.

Answer 1

Answer:

See answer in above attachment

Answer 2

The dimensional formula is [L]

Given:

h is height of liquid, S is surface tension, r is the radius, d is density of liquid and g is acceleration due to gravity.

To Find:

The dimensional formula for h = (2S cos(theta))/rdg

Solution:

From the given ,

we get,

h = $\frac{2S costheta}{rdg}$

LHS = [L]

Surface tension =S = F/I = $\frac{MLT^-2}{L}$

= [ $MT^-2$]

Radius = r = [ L]

g = [L$T^-2$]

RHS = $\frac{2S costheta}{rdg}$ = [$M^0L^1T^0$]

=[L]

LHS = RHS

Hence, the dimensional formula for the question is [L]

#SPJ2