Physics, asked by mamta44, 8 months ago

check whether the given equation is dimensionally correct, h=2 sigma.cos theta/rdg, where h is the height of the liquid, sigma is the surface tension of liquid, r is the radius of tube, d is the density of liquid and g is the acceleration due to gravity​

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Answered by Ashish871038
0

Answer:

Check the correctness of the relation h=2σcosθr2dg, where h is height , sigam is surface tension, θ is angle of contact, r is radius, d is density and g in acceleration due to gravity. AS LHS≠RHS, therefore, formula is wrong.

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