Math, asked by janveerharry23, 1 year ago

Check whether the given values are solutions of the given equation or not
x2 - 3x + 20 = 0 ; x = -2, 11.​

Answers

Answered by poonam05
10

Answer:

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Answered by sahilarora199587
7

Step-by-step explanation:

For checking, simply put the values in place of x in the given equation.

as the equation is

p(x) = x^2 - 3x + 20

now put x = -2 firs

p(-2) = (-2)^2 - 3(-2) + 20

= 4 + 6 + 20

= 30

therefore -2 is not the solution of given equation, as it will not give 0 at the end.

now

p(11) = (11)^2 - 3(11) + 20

= 121 - 33 + 20

= 88 +20

= 108

therefore 11 is not the solution of given equation, as it will not give 0 at the end.

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