Check whether the given values are solutions of the given equation or not
x2 - 3x + 20 = 0 ; x = -2, 11.
Answers
Answered by
0
Answer:
No
Step-by-step explanation:
putting x=-2 in the given equation
x^2-3x+20
=(-2)^2 -3(-2) +20
=4 +6 +20
=30 i.e. not equal to 0
putting x=11 in the given equation
x^2-3x+20
=(11)^2 -3(11) +20
=121-33+20
=108
again i.e.not equal to 0
so the given value of x does not satisfy the equation
henceforth,the given values are not the solutions of the given equation
Answered by
4
Answer:
Answer:
No
Step-by-step explanation:
putting x=-2 in the given equation
x^2-3x+20
=(-2)^2 -3(-2) +20
=4 +6 +20
=30 i.e. not equal to 0
putting x=11 in the given equation
x^2-3x+20
=(11)^2 -3(11) +20
=121-33+20
=108
again i.e.not equal to 0
so the given value of x does not satisfy the equation
henceforth,the given values are not the solutions of the given equation
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