Question

check whether the graph of the linear equation 2x+3y=12 passes through the point (1,3)

Answer 1

Step-by-step explanation:

If the graph passes through this point,

It must satisfy the equation.

Therefore,

LHS = 2 × 1 + 3×3 = 2 +9 = 11

RHS = 12

LHS is not equal to RHS.

Hence, (1,3) doesn't lie on line 2x + 3y = 12

Answer 2

Answer:

First, we rewrite the equation 2x+3y=12 in the form of y=mx+c.

2x+3y=12 implies y=−

3

2

x+4

Substituting x=−3,0,3 in the above equation, we find the values of y as follows

y=−

3

2

x+4

x −3 0 3

−

3

2

x 2 0 −2

y=−32

x+4 6 4 2

Plot the points (−3,6),(0,4) and (3,2) and draw a line passing through these points. Now we get the required graph.