Question

Check whether the point (3;1) lies on the equation 5x-15y=0

Answer 1

5×3-15×1=0
15-15=0
0=0
thus (3,1) lies

Answer 2

Given point = ( 3 , 1 )

( x , y ) = ( 3 , 1 )


×=×=×=×=×=×=×=×=×=×=×=×=×=×
x = 3 And y = 1
×=×=×=×=×=×=×=×=×=×=×=×=×=×


To prove : 5x - 15y = 0

LHS,
▶ 5( 3 ) - 15( 1 )
▶ 15 - 15
▶ 0

RHS,
▶0





$0 = 0$

LHS = RHS




Hence, point ( 3 , 1 ) lies on the equation 5x - 15y = 0