check whether the polynomial p(s)=3s^3+s^2-20s+12 is a multiple of 3s-2
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Answered by
98
Hlo friend.. Nice question .
Here is ur answer :
P(s) = 3s³+ s²-20s+12
G(s)= 3s-2
Put G(s) = 0
3s-2=0
3s = 2
S = 2/3
P(s) = 3s³+ s²-20s+12
P(2/3) = 3 (2/3)³ + (2/3)² - 20(2/3)+ 12
= 3 × 8/27 + 4/9 - 40/3 + 12
= 8/9 + 4/9 - 40/3 + 12
= 8+4/9 - 40/3 +12
= 12/9 - 40/3 + 12
= 4/3 - 40/3 + 12
= 4 - 40 / 3 + 12
= - 36/3 + 12
= - 12+12
= 0
Yes, 3s-2 is a multiple of P(s).
HOPE IT HELPS YOU...
REGARDS
@sunita
IF IT HELPS YOU SO PLS CLICK ON THANK YOU
Here is ur answer :
P(s) = 3s³+ s²-20s+12
G(s)= 3s-2
Put G(s) = 0
3s-2=0
3s = 2
S = 2/3
P(s) = 3s³+ s²-20s+12
P(2/3) = 3 (2/3)³ + (2/3)² - 20(2/3)+ 12
= 3 × 8/27 + 4/9 - 40/3 + 12
= 8/9 + 4/9 - 40/3 + 12
= 8+4/9 - 40/3 +12
= 12/9 - 40/3 + 12
= 4/3 - 40/3 + 12
= 4 - 40 / 3 + 12
= - 36/3 + 12
= - 12+12
= 0
Yes, 3s-2 is a multiple of P(s).
HOPE IT HELPS YOU...
REGARDS
@sunita
IF IT HELPS YOU SO PLS CLICK ON THANK YOU
Answered by
27
Answer:
Step-by-step explanatIon:
P(s) = 3s³+ s²-20s+12
G(s)= 3s-2
Put G(s) = 0
3s-2=0
3s = 2
S = 2/3
P(s) = 3s³+ s²-20s+12
P(2/3) = 3 (2/3)³ + (2/3)² - 20(2/3)+ 12
= 3 × 8/27 + 4/9 - 40/3 + 12
= 8/9 + 4/9 - 40/3 + 12
= 8+4/9 - 40/3 +12
= 12/9 - 40/3 + 12
= 4/3 - 40/3 + 12
= 4 - 40 / 3 + 12
= - 36/3 + 12
= - 12+12
= 0
Yes, 3s-2 is a multiple of P(s).
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