Check whether the polynomial :p(s) =3s^3+s^2-20s+12 is a multiple of 3s-2
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Answered by
7
ʜᴇʟʟᴏ ᴍᴀᴛᴇ!
p(s) = 3s³ + s² - 20s + 12
If 3s - 2 is multiple of p(s), then
s = 2/3
p(s) = 3(2/3)³ + (2/3)² - 20(2/3) + 12
0 = 3*8/27 + 4/9 - 40/3 + 12
0 = 8/9 + 4/9 - 120/9 + 108/9
0 = ( 8 + 4 - 120 + 108 )/9
0 = 120 - 120
0 = 0
Therefore 3s - 2 is multiple of given polynomial.
Hope it helps
p(s) = 3s³ + s² - 20s + 12
If 3s - 2 is multiple of p(s), then
s = 2/3
p(s) = 3(2/3)³ + (2/3)² - 20(2/3) + 12
0 = 3*8/27 + 4/9 - 40/3 + 12
0 = 8/9 + 4/9 - 120/9 + 108/9
0 = ( 8 + 4 - 120 + 108 )/9
0 = 120 - 120
0 = 0
Therefore 3s - 2 is multiple of given polynomial.
Hope it helps
inderjeetsjheepblldx:
Thank you so much dear
Your most welcm dear
Ma'am, ur answer is wrong.. kindly correct it
Thanks friend for pointing
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Answered by
4
hey!!!
p(s) = 3s³ + s² - 20s + 12
g(s) = 3s - 2
>> 3s - 2 = 0
= 3s = 2
= s = 2/3
on putting values :-
p(2/3) = 3(2/3)³ + (2/3)² - 20(2/3) + 12
= 3(8/27) + 4/9 - 40/3 + 12
= 8/9 + 4/9 - 40/3 + 12
= 12/9 - 40/3 + 12
= 4/3 - 40/3 + 12
= -36/3 + 12
= -12 + 12
= 0
remainder is 0, therefore 3s-2 is a factor of 3s³ + s² - 20s + 12
cheers!!!
p(s) = 3s³ + s² - 20s + 12
g(s) = 3s - 2
>> 3s - 2 = 0
= 3s = 2
= s = 2/3
on putting values :-
p(2/3) = 3(2/3)³ + (2/3)² - 20(2/3) + 12
= 3(8/27) + 4/9 - 40/3 + 12
= 8/9 + 4/9 - 40/3 + 12
= 12/9 - 40/3 + 12
= 4/3 - 40/3 + 12
= -36/3 + 12
= -12 + 12
= 0
remainder is 0, therefore 3s-2 is a factor of 3s³ + s² - 20s + 12
cheers!!!
Tysm dear
ur most wlcm :))
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