check whether the polynomial p(y)=4y³+4y²-y-1 is a multiple of 2y+1.
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Answered by
53
let we substitute 2y+1=0(as the factor therom states if p(a) is a factor of p(x) then p(a) is equal to 0)
y=-1/2
therefore substitute this value in the given question
4(-1/2)^3+4(-1/2)^2-(-1/2)-1
4(-1/8)+4(1/4)+1/2-1
by cancelling the values we get
-1/2+1+1/2-1
⇒0
so 2y+1 is the factor of 4y^3+4y^2-y-1
y=-1/2
therefore substitute this value in the given question
4(-1/2)^3+4(-1/2)^2-(-1/2)-1
4(-1/8)+4(1/4)+1/2-1
by cancelling the values we get
-1/2+1+1/2-1
⇒0
so 2y+1 is the factor of 4y^3+4y^2-y-1
Nishtha2:
thank u so much!!
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6
Answer:
1. let we substitute 2y+1=0(as the factor therom states if p(a) is a factor of p(x) then p(a) is equal to 0)y=-1/2therefore substitute this value in the
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