check whether the terms are AP or not 1, 1 1/2 ,2, 2 1/2, 3
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Answer:
Compare the given series with a
1
,a
2
,a
3
......, we get
a
2
−a
1
=1−1=0
a
3
−a
2
=1−1=0
a
4
−a
3
=1−1=0
This shows that the difference of a term and preceding term is always same.
Hence, the given sequence forms an A.P.
Step-by-step explanation:
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