Question

Check whether the value given in the brackets is a solution to the given equation or not:
(A) n + 5 = 19 (n = 1)
(B) 7n + 5 = 19 (n = –2)
(C) 7n + 5 = 19 (n = 2)
(D) 4p – 3 = 13 (p = 1)
(E) 4p – 3 = 13 (p = – 4)
(F) 4p – 3 = 13 (p = 0)​

Answer 1

Solution:

(A) n + 5 = 19 (n = 1)

Putting n = 1

L.H.S. = n + 5 = 1 + 5 = 6 ≠ 19 = R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, n = 1 is not a solution of the given equation, n + 5 = 19.

(B) 7n + 5 = 19 (n = –2)

Putting n = –2

L.H.S. = 7n + 5 = 7 × (–2) + 5 = –14 + 5 =

–9 ≠ 19 = R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, n = –2 is not a solution of the given equation, 7n + 5 = 19.

(C) 7n + 5 = 19 (n = 2)

Putting n = 2

L.H.S. = 7n + 5 = 7 × (2) + 5 = 14 + 5 = 19

= R.H.S.

As L.H.S. = R.H.S.

Therefore, n = 2 is a solution of the given equation, 7n + 5 = 19.

(D) 4p – 3 = 13 (p = 1)

Putting p = 1

L.H.S. = 4p – 3 = (4 × 1) – 3 = 1 ≠ 13 =

R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, p = 1 is not a solution of the given equation, 4p – 3 = 13.

(E) 4p – 3 = 13 (p = – 4)

Putting p = – 4

L.H.S. = 4p – 3 = 4 × (–4) – 3 = –16 – 3 =

–19 ≠ 13 = R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, p = – 4 is not a solution of the given equation, 4p – 3 = 13.

(F) 4p – 3 = 13 (p = 0)

Putting p = 0

L.H.S. = 4p – 3 = (4 × 0) – 3 = – 3 ≠ 13 = R.H.S. As L.H.S. ≠ R.H.S.

Therefore, p = 0 is not a solution of the given equation, 4p – 3 = 13.

Thanks ..!!

Answer 2

Answer:

A) n + 5 = 19 (n = 1)

=) n + 5 = 19

putting n = 1

=) 1 + 5 = 19

=) 6 = 19

It is not true.

Hence, n = 1 is not a solution .

B) 7n + 5 = 19 (n = -2)

=) 7n + 5 =19

putting n = -2

=) 7(-2) + 5 = 19

=) -14 + 5 = 19

=) -9 = 19

It is not true.

Hence, n = -2 is not a solution.

C) 7n + 5 = 19 (n = 2)

=) 7n + 5 = 19

putting n= 2

=) 7(2) + 5 = 19

=) 14 + 5 = 19

=) 19 = 19

It is true.

Hence, n = 2 is a solution.

D) 4p - 3 = 13 (p = 1)

=) 4p - 3 = 13

putting p = 1

=) 4(1) - 3 = 13

=) 4 - 3 = 13

=) 1 = 13

It is not true.

Hence, p = 1 is not a solution.

E) 4p - 3 = 13 (p = -4)

=) 4p - 3 = 13

putting p = -4

=) 4(-4) - 3 = 13

=) -16 - 3 = 13

=) -19 = 13

It is not true.

Hence, p = -4 is not a solution.

F) 4p - 3 = 13 (p = 0)

=) 4p - 3 = 13

putting p = 0

=) 4(0) - 3 = 13

=) -3 = 13

It is not true.

Hence, p = 0 is not a solution.