check whether the value given in the brackets is the root
of the given equation or not.
a)2(x-3)=-12[x=3]
b)8x-4=0[x=1/2]
please please who will give first answer i wull mark brainleast and follow he/she it to urgent plz
plz
Answers
Answer:
a.) 2(3-3)=-12
2×0=0
o is not equal to 12 so it is not the root
of the given equation
b.)8×1/2-4=0
4×1-4=0
4-4=0
0 is equal to 0 so it is the root
of the given equation
Step-by-step explanation:
bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10hey guys good morning help me see in the pic
pleastell share the screen shot or pic of this daturoopdear all please.dont irrevant question in this app this is a study platforms dear please this is my humble request to you all .pleaseinsert four rational numbers between -8/13and 5/39
please matesbp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10dear all please.dont irrevant question in this app this is a study platforms dear please this is my humble request to you all .pleasehey guys good morning help me see in the pic
pleastell share the screen shot or pic of this daturoopbp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10dear all please.dont irrevant question in this app this is a study platforms dear please this is my humble request to you all .pleasebp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10dear all please.dont irrevant question in this app this is a study platforms dear please this is my humble request to you all .pleasehey guys good morning help me see in the pic
pleastell share the screen shot or pic of this daturoopbp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10