Question

Check whether the vaue in the bracket is a solution to the given Equation Or Not :

A) N + 5 = 19 ( N = 1 )
B) 4p - 3 = ( P = - 4) ​

Answer 1

Answer:

(A) n + 5 = 19 (n = 1)

Putting n = 1

L.H.S. = n + 5 = 1 + 5 = 6 ≠ 19 = R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, n = 1 is not a solution of the given equation, n + 5 = 19.

(B) 7n + 5 = 19 (n = –2)

Putting n = –2

L.H.S. = 7n + 5 = 7 × (–2) + 5 = –14 + 5

= –9 ≠ 19 = R.H.S.

As L.H.S. ≠ R.H.S.

Therefore, n = –2 is not a solution of the given equation, 7n + 5 = 19.

(B) 4p – 3 = 13 (p = – 4)

Putting p = – 4

L.H.S. = 4p – 3 = 4 × (–4) – 3 = –16 – 3

= –19 ≠ 13 = R.H.S.

As L.H.S. ≠ R.H.S.,

Therefore, p = – 4 is not a solution of the given equation, 4p – 3 = 13.

(F) 4p – 3 = 13 (p = 0)

Putting p = 0

L.H.S. = 4p – 3 = (4 × 0) – 3 = – 3 ≠ 13 = R.H.S. As L.H.S. ≠ R.H.S.,

Therefore, p = 0 is not a solution of the given equation, 4p – 3 = 13.

Answer 2

Answer:

A) No

Sorry I don't know the B one