Check whether the zeroes of x^2-5x+6 is a solution of linear equations x+y=5 and x-y=1
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Answer:
x = 3.
Step-by-step explanation:
x^2-5x+6.
(x^2-3x) - (2x+3).
x(x-3)-2(x-3).
x = 3,2.
If x=3,
then satisfaction of x+y=5,x-y=1.
If x=2 the linear equations will not be satisfied.
So, x= 3 is the solution of the linear equations.
Hope it helps you....
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