Question

Check whether (x+1)^2=3(x+7) is a quadratic equation or not​

Answer 1

Answer:

${x}^{2} + 1 + 2x = 3x + 21 \\ {x}^{2} + 1 - 21 + 2 x - 3x = 0 \\ {x}^{2} - 20 - 1x = 0 \\ {x}^{2} - 1x - 20 = 0$

so , the given equation is a quadratic equation

Answer 2

Answer:

Yes

Step-by-step explanation:

(x+1)² = 3(x+7)

By using identity, (a+b)² = a² + 2ab + b²

x² + 2x + 1 = 3x + 21

Now transposing all to left side,

x² + 2x +1 - 3x - 21 = 0

x² - x - 20 = 0

Therefore, this equation has highest degree as 2 so it is an quadratic equation.