Check whether (x – 1) is a factor of 7x3 + 2x2 – x + 8.
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Answer:
(x-1) is a factor
then x-1=0
x=1
putting value of x in p(x)
p(x)= 7x³+2x²-x+8
p(1)= 7(1)³+2(1)²-(1)+8
7(1)³+2(1)²-1+8=0
7+2-1+8=0
9+7=0
16≠0
LHS≠RHS
Therefore (x-1) is not a factor.
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