Question

check whether (x-1) is a factor of the polynomial x2-27x2+8x+18

Answer 1

using division method
I we give zero then x-1 is factor of given polynomial

Answer 2

$x - 1$
$x = 1$
$p(x) = {x}^{3} - 27 {x}^{2} + 8x + 18$
$p(1) = 1 {}^{3} - 27(1) + 8(1) + 18$
$0 = 1 - 27 + 8 + 18$
$0 = 1 - 53$
$0 = - 52$
$so \: \\ x - 1 \: is \: not \: a \: factor \: of \: p(x)$


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