Question

Check whether (x-2)is a factor of x cube -2x square-5x+4​

Answer 1

Answer:

p(x)=x³-2x²-5x+4

q(x)=x-2

$x - 2 = 0 \\ = x = 2$

putting x=2 in p(x)

$x {}^{3} - 2x {}^{2} - 5x + 4 \\ = ( {2)}^{3} - 2 \times {2}^{2} - 5 \times 2 + 4 \\ = 8 - 2 \times 4 - 10 + 4 \\ = 8 - 8 - 10 + 4 \\ - 6$

so, p(x) is not a fector of q(x)

hope IT HELPs....