Question

check whether (x-2) is a factor of x cube -2x square-5x+4​

Answer 1

Answer:

X-2=0

X=2

P(X)=x^3-3x^2+3x-2

Putting the value of X=2

=2^3-3×2^2+3×2-2

=8-12+6-2

=-14+14

=0

So x-2 is a factor

Step-by-step explanation:

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Answer 2

Answer:

-6

Step-by-step explanation:

p(x)=x^3-2x^2-5x+4. g(x)=(x-2)

x-2=0

x=2

p(2)=(2^3)-2(2^2)-5(2)+4

p(2)=8-8-10+4

p(2)=-6

Since remainder is not zero, (x-2) is not a factor of p(x)