check whether x+3 is a factor of x²-12x-45
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Answered by
0
Answer:
it is a factor
Step-by-step explanation:
x+3=0
x=-3
putting value in polynomial,
(-3)^2-(12*-3)-45
=9+36-45
=0
therefore it is a factor
Answered by
0
f(x)=x^2+12x-45
p(x)=x+3
put p(x)=0
0=x+3
x=-3
Put x=-3 in f(x)
f(-3)=(-3)^2-12(-3)-45
=9+36-45
=45-45
=0
Hence , x+3 is a factor of f(x)
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