check whether (x-3) is a factor of x³-2x²-5x+4
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Step-by-step explanation:
If x+2 is a factor of the above cubic equation then the result after putting the values will be 0
x+2=0
x=-2
\begin{gathered} = x {}^{3} - 2x {}^{2} - 5x + 4 \\ = ( - 2) {}^{3} - 2( -2) {}^{2} - 5( - 2 ) + 4 \\ = - 8 -2 (4) + 10 + 4 \\ = - 8 - 8 + 10 + 4 \\ = - 16 + 10 + 4 \\ = - 6 + 4 \\ = - 2\end{gathered}
=x
3
−2x
2
−5x+4
=(−2)
3
−2(−2)
2
−5(−2)+4
=−8−2(4)+10+4
=−8−8+10+4
=−16+10+4
=−6+4
=−2
The result is not 0 hence it is not the factor of the above equation.
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