Question

check whether x=5,x=-2 are the solutions of the equation x^-3x+10​

Answer 1

Step-by-step explanation:

Given equation is x²-3x+10=0

if any number satisfies the given equation then it is a solution of the given equation. ie.

LHS =RHS

put x=5 then

LHS=>52-3(5)+10

=>25-15+10

=>35-15

=>20

LHS≠RHS

5 is not a solution

Put x=-2 then

LHS=(-2)²-3(-2)+10

=>4+6+10

=>20

=>20

LHS≠RHS

-2 is not a solution

5 and -2 are not solutions