check whether (x+ I) is a factor of x³ + x²+x+1
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Answer:
Yes
Step-by-step explanation:
x + 1 = 0
x = -1
Therefore, substituting the value x by -1,
⇒ (-1)³ + (-1)² + (-1) + 1 should be = 0
⇒ -1 + 1 - 1 + 1
⇒ 0
Hence, x + 1 is a factor of the given polynomial.
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