Question

check whether x(x+1)+8=(x+2)(x-2) is quadratic equation​

Answer 1

Answer:

amswer is no

Step-by-step explanation:

x²+x = x² - 4

x²-x²+x+4 =0

x+4=0

hence it is not a quadratic equation

Answer 2

➲T0 CHECK :

• $\bf{x(x+1)+8 = (x+2) (x-2)}$, is a quadratic equation or not.

➲SOLUTION :

• Simplifying :

${:}\longrightarrow \sf x(x+1)+8 = (x+2) (x-2)$

• Using distributive law and $\bf{(a + b)(a - b) = {a}^{2} - {b}^{2} }$

${:}\longrightarrow \sf x(x+1)+8 = (x+2) (x-2)$

${:}\longrightarrow\sf x^2+x+8=(x)^2 - (2)^2$

${:}\longrightarrow\sf x^2+x+8=x^2-4$

${:}\longrightarrow\sf x^2+x+8-x^2+4=0$

${:}\longrightarrow \sf \cancel{x^2}-\cancel{x^2}+x+8+4= 0$

${:}\longrightarrow \sf x+8+4 =0$

${:}\longrightarrow \sf x+12 =0$

This equation is not of this type :$\bf{ax^2 + bx + c = 0}$

$\huge{ \pink{ \therefore}}$ $\bf{x(x+1)+8=(x+2)(x-2)}$, is not a quadratic equation.