check whether {x:x^2=25 and 6x=15} is an empty set or not?justify your answer.
Answers
Answered by
124
Answer :-
Empty set
Solution :-
Let, A = { x : x² = 25 and 6x = 15 }
Finding x when x² = 25
⇒ x² = 25
⇒ x = √25
⇒ x = ± 5
⇒ x = 5 or - 5
Finding x when 6x = 15
⇒ 6x = 15
⇒ x = 15 / 6
⇒ x = 2.5
Since, the value of x in both cases are different there is no value of x that satisfies the given rule.
So, the set A = Φ
Therefore the set { x : x² = 25 and 6x = 15 } is an empty set.
Answered by
66
Answer:
Empty set
Solution :-
Let, A = { x : x² = 25 and 6x = 15 }
Finding x when x² = 25
⇒ x² = 25
⇒ x = √25
⇒ x = ± 5
⇒ x = 5 or - 5
Finding x when 6x = 15
⇒ 6x = 15
⇒ x = 15 / 6
⇒ x = 2.5
Since, the value of x in both cases are different there is no value of x that satisfies the given rule.
So, the set A = Φ
Therefore the set { x : x² = 25 and 6x = 15 } is an empty set.
Similar questions