Math, asked by TANU81, 1 year ago

◆Check whether x²+2√x-3=0 is a quadratic equation or not ?

◆Find the roots of (x+7) (x+4)=0

◆Solve 5x²-17x+12=0 by factorisation method.

◆Solve a²b²x²+b²x-a²x-1 =0


rohitkumargupta: check your first question
rohitkumargupta: plz
rohitkumargupta: it is x² + 2√x + 1??
TANU81: No
TANU81: its x²+2√x -3
Soumyadwip: Question is correct
Soumyadwip: Check my answer
TANU81: =0
rohitkumargupta: whi

Answers

Answered by Soumyadwip
14
The answer is attached herewith.
Contact me for any further difficulties or explanations.
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Soumyadwip: Welcome
rohitkumargupta: :-)♥️
Answered by abhi569
7
(1):

If it is a quadratic equation, it must be in the form of (ax²+bx+c=0) and a≠0


As we can observe that

ax² = x² where a = 1
2√x = bx where b = 2
-3 = c where c = -3



Hence, this is a quadrilateral equation.







(2):

(x + 7)(x + 4) = 0

By Zero Product Rule, Anything multiplied by 0 is equal to 0, So (x + 7) can be 0 or (x + 4) can be 0

=> (x + 7 = 0) or (x + 4 = 0)

=> (x = -7) or (x = -4)



(3):


5x² - 17x + 12 = 0

5x² - (12 + 5)x + 12 = 0

5x² - 12x - 5x + 12 =0

x(5x - 12) - 1(5x - 12) = 0

(x - 1)(5x - 12) = 0


(x = 1). Or. ( x = 12/5)




(4):
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TANU81: ^_^
abhi569: :-)
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