check whether y=1 is zero of y3-5y2+7Y-3 OR NOT
Answers
Answered by
0
Yeah it comes to zero as you substitute the value of y =1
Y^3 = 1
-5Y^2 = -5
+7Y= 7
-3 = -3
1-5+7-3 = 0
Y^3 = 1
-5Y^2 = -5
+7Y= 7
-3 = -3
1-5+7-3 = 0
Anonymous:
my dear we have to substitute the value as 1 not -1 .....plzz edit that
okkkkkkkk
whatever!!!
Y=1
yupp @saklani2003
Answered by
3
y³-5y²+7y-3
→ y = 1
(1)³-5(1)²+7(1)-3
= 1-5(1)+7-3
= 1-5+7-3
= 8-8
= 0
So,y=1 is a zero of the given polynomial.
Hope it helps
→ y = 1
(1)³-5(1)²+7(1)-3
= 1-5(1)+7-3
= 1-5+7-3
= 8-8
= 0
So,y=1 is a zero of the given polynomial.
Hope it helps
Tks
divide x101+101 by x+1
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