Check whether y - 3 is a factor of y3 – 2y2 + 3y - 18?
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Answer:
Given, (y−3) is the factor of y
3
+2y
2
−9y−18
Then y−3=0 or y=3
Replace y by 3, we get
y
3
+2y
2
−9y−18
=(3)
3
+2(3)
2
−9(3)−18
=27+18−27−18
=0
As value is zero, then (y−3) is the factor of y
3
+2y
2
−9y−18.
y
3
+2y
2
−9y−18
=y
3
−3y
2
+5y
2
−15y+6y−18
=y
2
(y−3)+5y(y−3)+6(y−3)
=(y−3)(y
2
+5y+6)
=(y−3)(y
2
+2y+3y+6)
=(y−3)[y(y+2)+3(y+2)]
=(y−3)(y+2)(y+3)
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