check whether y(8y+5)=y²+3 is a quadratic equation
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Answered by
2
Answer:
(y^2)+8y+16=0
(y^2)+4y+4y+16=0
(y^2+4y)+(4y+16)=0
{y(y+4)}+{4(y+4)}=0 y(y+4)+4(y+4)=0 (y+4)(y+4)=0
(OR)
(y^2)+8y+16=0
(y^2)+(2xyx4)+(4^2)=0 (y+4)^2=0
(y+4)(y+4)=0
From both we get:
y+4=0
y=0-4
y=-4
Answered by
4
Answer:
(y^2)+8y+16=0
(y^2)+4y+4y+16=0
(y^2+4y)+(4y+16)=0
[y(y+4)]+(4(y+4)]=0 y(y+4)+4(y+4)=0 (y+4) (y+4)=0
(OR)
(y^2)+8y+16=0
(y^2)+(2xyx4)+(4^2)=0 (y+4)^2=0
(y+4)(y+4)=0
From both we get:
y+4=0
y=0-4
y=-4
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