Question

check which is the following is the solution of the equation x-2y=4​

Answer 1

Answer:

There is infinite amount of solutions for the given equation

Some of these solutions are :

1. (2, -1)
2. (4, 0)
3. (-2, -3)

Step-by-step explanation:

$\blacksquare$ x - 2y = 4 is a linear equation in two variables (x and y)

$\blacksquare$ Since it is a linear equation, its graph will be a straight line having infinite amount of points

$\blacksquare$ If we put any values for x or y we will get correspnding y and x values

$\blacksquare$ For example,

If x = 2,                            If x = 4,                          If x = -2,

2 - 2y = 4                          4 - 2y = 4                        -2 - 2y = 4

-2y = 4 - 2                         -2y = 4 - 4                       -2y = 4 + 2

-2y = 2                               -2y = 0                            -2y = 6

y = -1                                    y = 0                                 y = -3

$\blacksquare$ Hence,

(2, -1), (4, 0), (-2, -3) are some of the points on the line x - 2y = 4

Answer 2

(i) (0, 2)

(x,y) = (0,2)

Here, x=0 and y=2

Substituting the values of x and y in the equation x–2y = 4, we get,

x–2y = 4

⟹ 0 – (2×2) = 4

But, -4 4

(0, 2) is not a solution of the equation x–2y = 4

(ii) (2, 0)

(x,y) = (2, 0)

Here, x = 2 and y = 0

Substituting the values of x and y in the equation x -2y = 4, we get,

x -2y = 4

⟹ 2-(2×0) = 4

⟹ 2 -0 = 4

But, 2 ≠ 4

(2, 0) is not a solution of the equation x-2y = 4

(iii) (4, 0)

Solution:

(x,y) = (4, 0)

Here, x= 4 and y=0

Substituting the values of x and y in the equation x -2y = 4, we get,

x–2y = 4

⟹ 4 – 2×0 = 4

⟹ 4-0 = 4

⟹ 4 = 4

(4, 0) is a solution of the equation x–2y = 4

(iv) (√2,4√2)

Solution:

(x,y) = (√2,4√2)

Here, x = √2 and y = 4√2

Substituting the values of x and y in the equation x–2y = 4, we get,

x –2y = 4

⟹ √2-(2×4√2) = 4

√2-8√2 = 4

But, -7√2 ≠ 4

(√2,4√2) is not a solution of the equation x–2y = 4

(v) (1, 1)

Solution:

(x,y) = (1, 1)

Here, x= 1 and y= 1

Substituting the values of x and y in the equation x–2y = 4, we get,

x –2y = 4

⟹ 1 -(2×1) = 4

⟹ 1-2 = 4

But, -1 ≠ 4

(1, 1) is not a solution of the equation x–2y = 4.