Math, asked by ankitha14, 1 year ago

check x-2 is a factor of x³-3x²+2x-1.

Answers

Answered by puja77
8
hey there !

x-2=0

=> x= 2

p(2)= (2)³-3(2)²+2(2)-1

= 8-12+4-1

= 12-12-1

= -1

no, x-2 is not a factor of p(x) x³-3x²+2x-1

hope it helps

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Answered by Anonymous
4
Hello here,

Answer -----

Sol.

Here , P(x) is x³-3x²+2x-1 and g(x) is x-2

The zero of x-2 is 2
by remainder theorem,
when , x³-3x²+2x-1 is divided by x-2,

=> P(x) = x³-3x²+2x-1

=>P(2) = 2³-3(2)²+2(2)-1

=> 8 -12+4-1

=> -1

so, g(x) is not a factor of given polynomial P(x).

Hope it's helps you.
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