Question

checking the formula v2=u2+2as

Answer 1

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From 1st equation of motion,

V = U +AT

Therfore, V - U = AT …eq 1

Weknow that

S = (U + V / 2 )×T

∴ S/T = U + V / 2

∴U + V = 2×S/T

∴ U + V = 2S / T … eq2

So Substituting eq1 and eq2,

(V - U ) (V + U ) = AT ×2S/T

∴V² - U² = 2AS.

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Answer 2

First of all you have to know the other two equations of motions :

V= u+atS= ut+1\2 at^2

Now the derivation:

From the first equation we have :

at=v-u

t=v-u\a

Now putting the value of t in the second equation of motion:

s=u(v-u\a)+1\2 a(v-u\a)^2

s= uv-u^2\a+a(v^2+u^2–2vu)\2a^2

s=uv-u^2\a+(v^2+u^2+2vu)\2a

s= (2uv-2u^2+v^2+u^2–2vu)\2a

2as=v^2-u^2

v^2=u^2+2as

So here it is.. hope it helps :)

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