Question

cheetah can start from rest and attain velocity 72 km/h in 4 seconds calculate the acceleration of cheetah​

Answer 1

Acceleration = Final velocity - Initial velocity

_____________________

Time taken for change in velocity

Final velocity = 72 km/h = (72 × ⁵/¹⁸ ) m/s

= 20 m/s

intial velocity = 0

Time taken for change in velocity = 2s

Acceleration = 20 - 0 20

______ = _____ = 10 m/s²

2 2

Answer 2

Given :-

Final velocity of the cheetah = 72 km/h

Time taken by the cheetah = 4 sec

To Find :-

The acceleration of the cheetah.

Analysis :-

Here we are given with the final velocity and the time taken by the cheetah.

In order to find the acceleration of the cheetah, substitute the values given in the first equation of motion.

Solution :-

We know that,

• a = Acceleration
• v = Final velocity
• t = Time
• u = Initial velocity

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Final velocity (v) = 72 km/h = 20 m/s

Initial velocity (u) = 0 m/s

Time (t) = 4 sec

Substituting their values,

⇒ 20 = 0 + (a) × 4

⇒ a = (v-u) / t

⇒ a = (20 - 0) / 4

⇒ a = 20/4

⇒ a = 5 m/s

Therefore, the acceleration of the cheetah is 5 m/s.