Physics, asked by panwarrudraksh, 17 days ago

Cheetah runs for 40 minutes at 100km/hr, then stops for 15 minutes and then runs again
in the same direction at 80km/hr for one hour. Find the magnitude of its average velocity
in km/hr. (Answer up to two decimal places)

Answers

Answered by brainlyuser510
0

Answer:

Explanation:living organism of the kind exemplified by trees, shrubs, herbs, grasses, ferns, and mosses, typically growing in a permanent site, absorbing water and inorganic substances through its roots, and synthesizing nutrients in its leaves by photosynthesis using the green pigment chlorophyll.

Answered by UsmanSant
1

The average velocity of the cheetah is 765.21 km/hr.

Given:

The Cheetah runs for 40 minutes at 100km/hr, then stops for 15 minutes, and then runs again in the same direction at 80km/hr for one hour.

To Find:

We need to find the average velocity in km/hr.

Solution:

Here to find the average velocity we need to find the total displacement made by the cheetah and divide it by the total amount of time the cheetah took to cover up its displacement.

Let,

Average velocity = V

Total displacement = d

Total time = t

Thus, the formula arises as,

V = d/t

Now, for getting the value of average velocity in km/hr, we need to convert all of the time from minutes to hours.

Now,

In the first part, Cheetah traveled for 40 mins (i.e, 40/60 hr) at 100 km/hr.

Thus the displacement that is done by Cheetah in the first half,

d₁ = \frac{100 * 40}{60} km

= 4000/6 km

And, let the time taken to travel in the first half is, t₁ = 40/60 hr

Now, in the second part, the cheetah waited for 15 mins.

i,e,

Let, t₂ = 15/60 hr.

And lastly, The cheetah runs at 80 km/hr for one hour.

i.e,

displacement made, d₂ = (80 × 1) km

or, d₂ = 80 km

let, time taken, t₃ = 1 hr.

Another thing to note is that the cheetah runs in the same direction from the very beginning.

Thus the average velocity,

V = \frac{d_{1} +d_{2} }{t_{1}+ t_{2}+ t_{3} }

= \frac{\frac{4000}{6}+80 }{\frac{40}{60}+\frac{15}{60}+1  }

= \frac{\frac{8800}{6} }{\frac{115}{60} }

= \frac{8800*60}{6*115}

= 765.21 km/hr

Thus the average velocity of the cheetah is 765.21 km/hr.

#SPJ2

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